Note: Below algorithms turns out to be not sufficient. The edit script for the following case is incomplete. Given S constructed from an empty tree
S = +/s:{} +/t:{}
obtain T from S by
T = S +/s/a:{} >/s:/t/s
Running below algorithm on S and T will result in an edit script which, when applied to S, will not create child node a. I.e. it will result in
S >/s:/t/s
An algorithm for creating edit scripts (in JSOP format) from two trees. See this GitHub repository for a proof of concept implementation and the related discussion on oak-dev@
// Global variable holding the JSOP journal after the diffTree below returns.
jsop = ""
/*
Create a JSOP journal, which when applied to tree S will transform
it to tree T.
*/
diffTrees(S, T) {
// Create a location (trash) which will temporarily hold removed nodes.
// This is necessary since these (or child nodes thereof) might still be
// needed in move operations occurring only later in the differencing process.
X = S.addNode(createUniqueName)
// The main differencing process starts at the roots of the trees and
// progresses recursively level by level.
diffNodes(X, S, T)
// Remove the trash location and all its content
jsop += "-" + X.path
}
/*
Recursively create JSOP operations for the differences of the children
of trees S and T. Tree X serves as trash.
*/
diffNode(X, S, T) {
deleted = S.childNames \ T.childNames // set difference
added = T.childNames \ S.childNames
// Need to take care of deleted nodes first in order to avoid
// name clashes when adding new nodes later.
for (d : deleted) {
t = S.child(d)
// Deleted nodes are moved to trash.
op = ">" + t.path + ":" + X.path + "/" + createUniqueName
jsop += op
S.apply(op) // Transform S according to the single op
}
for (a : added) {
t = T.child(a)
// assume we can detect a copied node and know its source node
if (isCopied(t)) {
op = "*" + t.sourceNode.path + ":" + t.path
}
// assume we can detect a moved node and know its source node
else if (isMoved(t)) {
op = ">" + t.sourceNode.path + ":" + t.path
}
// this is an added node
else {
op = "+" + t.path
}
jsop += op
S.apply(op) // Transform S according to the single op
}
// assert S.childNames == T.childNames
for (c : T.childNames) {
diffNode(X, S.child(c), T.child(c))
}
}