set hive.map.aggr=false;
set hive.multigroupby.singlereducer=false;
set hive.groupby.skewindata=true;

-- SORT_QUERY_RESULTS

CREATE TABLE dest1(key INT, val1 INT, val2 INT);
CREATE TABLE dest2(key INT, val1 INT, val2 INT);

CREATE TABLE INPUT(key INT, value STRING) STORED AS TEXTFILE;
LOAD DATA LOCAL INPATH '../../data/files/kv5.txt' INTO TABLE INPUT;

EXPLAIN
FROM INPUT 
INSERT OVERWRITE TABLE dest1 SELECT INPUT.key, count(substr(INPUT.value,5)), count(distinct substr(INPUT.value,5)) GROUP BY INPUT.key
INSERT OVERWRITE TABLE dest2 SELECT INPUT.key, sum(substr(INPUT.value,5)), sum(distinct substr(INPUT.value,5))   GROUP BY INPUT.key;

FROM INPUT
INSERT OVERWRITE TABLE dest1 SELECT INPUT.key, count(substr(INPUT.value,5)), count(distinct substr(INPUT.value,5)) GROUP BY INPUT.key
INSERT OVERWRITE TABLE dest2 SELECT INPUT.key, sum(substr(INPUT.value,5)), sum(distinct substr(INPUT.value,5))   GROUP BY INPUT.key;

SELECT * from dest1;
SELECT * from dest2;

set hive.multigroupby.singlereducer=true;

EXPLAIN
FROM INPUT 
INSERT OVERWRITE TABLE dest1 SELECT INPUT.key, count(substr(INPUT.value,5)), count(distinct substr(INPUT.value,5)) GROUP BY INPUT.key
INSERT OVERWRITE TABLE dest2 SELECT INPUT.key, sum(substr(INPUT.value,5)), sum(distinct substr(INPUT.value,5))   GROUP BY INPUT.key;

FROM INPUT
INSERT OVERWRITE TABLE dest1 SELECT INPUT.key, count(substr(INPUT.value,5)), count(distinct substr(INPUT.value,5)) GROUP BY INPUT.key
INSERT OVERWRITE TABLE dest2 SELECT INPUT.key, sum(substr(INPUT.value,5)), sum(distinct substr(INPUT.value,5))   GROUP BY INPUT.key;

SELECT * from dest1;
SELECT * from dest2;

-- HIVE-3852 Multi-groupby optimization fails when same distinct column is used twice or more
EXPLAIN
FROM INPUT
INSERT OVERWRITE TABLE dest1 SELECT INPUT.key, sum(distinct substr(INPUT.value,5)), count(distinct substr(INPUT.value,5)) GROUP BY INPUT.key
INSERT OVERWRITE TABLE dest2 SELECT INPUT.key, sum(distinct substr(INPUT.value,5)), avg(distinct substr(INPUT.value,5)) GROUP BY INPUT.key;

FROM INPUT
INSERT OVERWRITE TABLE dest1 SELECT INPUT.key, sum(distinct substr(INPUT.value,5)), count(distinct substr(INPUT.value,5)) GROUP BY INPUT.key
INSERT OVERWRITE TABLE dest2 SELECT INPUT.key, sum(distinct substr(INPUT.value,5)), avg(distinct substr(INPUT.value,5)) GROUP BY INPUT.key;

SELECT * from dest1;
SELECT * from dest2;